C++ || STL || standard template libraries

-
Image
                                       C++ STL  1.      Pair :  Syntax :      pair <int,char> p1;     it creates a pair {2,'c'} like this.           pair <int,int> p2;     it creates a pair {2,3} like this .  Basic Code :  #include <bits/stdc++.h> using namespace std; int main() {     // cout<<"hello world\n";     pair <int,int> p1 = {1,2};     cout<<p1.first<< " "<< p1.second<<endl;          pair <int, pair<int ,char>> p2 = {1,{2,'c'}};     cout<<p2.first<<" "<<p2.second.first<<" "<<p2.second.second<<endl;          pair <int,int> arr[] = {{2,3},{4,5},{6,7}};     cout...
Post a Comment

Find the second lowest grade in the nested list:

-

Given the names and grades for each student in a class of  students, store them in a nested list and print the name(s) of any student(s) having the second lowest grade.


Hacker Rank Solution:  

 if __name__ == '__main__':

    student_list = []
    for _ in range(int(input())):
        name = input()
        score = float(input())
        student_list.append([name,score])
    # print(student_list)    
    
scores_list = sorted(list(set([student[1] for student in student_list])))
# print(scores_list)
second_lowest_grade = scores_list[1]
student_second_lowest_grade = [
    student[0] 
    for student in student_list
    if(student[1]==second_lowest_grade)


]
student_second_lowest_grade.sort()
for i in student_second_lowest_grade:
    print(i)

Comments

Post a Comment

Popular posts from this blog

1050. Actors and Directors Who Cooperated At Least Three Times || Leetcode sql solution || Simple and Easy Approach || ✅✅✅✅💯💯💯🔥🔥🔥🔥

-
  Actors and Directors Who Cooperated At Least Three Times || Leetcode sql solution || Simple and Easy Approach || ✅✅✅✅💯💯💯🔥🔥🔥🔥 Link For The Question :   Actors and Directors Who Cooperated At Least Three Times SQL SOLUTION : USING   GROUP BY: select actor_id , director_id from ( select actor_id , director_id , count ( timestamp ) as cooperated from ActorDirector group by actor_id , director_id ) as table1 where cooperated >= 3 ; GROUP WITH HAVING CLAUSE: select actor_id , director_id from ActorDirector group by actor_id , director_id Having count ( timestamp ) >= 3 ;
Read more

Power of Millets || Happy And Healthy Life

-
Image
Foundation Day Meeting : By   D. Anjaneyulu Reddy : Power of millets: When food is right no medicine is needed. When food is wrong no medicine works 1. Cosmetologist : due to unbalanced diet, regularly going to cosmetologist 2. Harmonal imbalance : hair loss 3. 1 gm of sugar / 1 litre of blood : It is good for health. 4. Staple food : It is eaten regularly , large part of person's diet. 5. Don't eat icecream as it increase the sugar content in blood. Embrace meaning : include , hug
Read more

c program to clear nth bit of the number || Bitwise Operators || Problem Solving ||

-
#include <stdio.h> int main() {     int num, n, newNum;     printf("Enter any number: ");     scanf("%d", &num);     printf("Enter nth bit to clear (0-31): ");     scanf("%d", &n);     newNum = num & (~(1 << n));     printf("Number before clearing %d bit: %d (in decimal)\n", n, num);     printf("Number after clearing %d bit: %d (in decimal)\n", n, newNum);     return 0; } Logic :-  num&(~(1<<n));
Read more